Capturing an array in C++ lambda

Question | Jul 9, 2016 | nextptr 

C++ lambda expressions can capture their surrounding scope variables either by value (=) or by reference(&). You can use the lambda capture clause - square brackets [ ] - to indicate which variables need to be captured and how (value or reference). For an introduction to lambda expressions read "Lambda Expressions in C++".

This code captures an array by value in a lambda, modifies the array after the definition of lambda, and then calls that lambda function:

// create and initialize array with all 0s
int collection[5] = {};

// capture collection by value
auto process = [=]() {
    for(int i : collection)
        std::cout << i << " ";

// modify the array elements 
for(int i=0; i < 5; ++i)
    collection[i] = i;

// call lambda

What do you think would be the output of calling process?